Base | Representation |
---|---|
bin | 1100001100000011011011… |
… | …1110100011111011110111 |
3 | 1202110010220002100020212001 |
4 | 3003000312332203323313 |
5 | 3224031144401131203 |
6 | 44300234032440131 |
7 | 2552130506225425 |
oct | 303006676437367 |
9 | 52403802306761 |
10 | 13401220333303 |
11 | 42a7475566610 |
12 | 16052b56a9047 |
13 | 762964089c6a |
14 | 3448a02cc115 |
15 | 1838e328591d |
hex | c3036fa3ef7 |
13401220333303 has 8 divisors (see below), whose sum is σ = 14959501767936. Its totient is φ = 11899603678200.
The previous prime is 13401220333247. The next prime is 13401220333309. The reversal of 13401220333303 is 30333302210431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13401220333303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13401220333309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14166194383 + ... + 14166195328.
It is an arithmetic number, because the mean of its divisors is an integer number (1869937720992).
Almost surely, 213401220333303 is an apocalyptic number.
13401220333303 is a deficient number, since it is larger than the sum of its proper divisors (1558281434633).
13401220333303 is a wasteful number, since it uses less digits than its factorization.
13401220333303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28332389765.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 13401220333303 its reverse (30333302210431), we get a palindrome (43734522543734).
The spelling of 13401220333303 in words is "thirteen trillion, four hundred one billion, two hundred twenty million, three hundred thirty-three thousand, three hundred three".
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