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13401221021323 = 109181316781037
BaseRepresentation
bin1100001100000011011100…
…0001001011111010001011
31202110010220010122012122021
43003000313001023322023
53224031200040140243
644300234055305311
72552130515122342
oct303006701137213
952403803565567
1013401221021323
1142a7475996523
1216052b597b237
1376296426b185
143448a042ab59
151838e336e6ed
hexc303704be8b

13401221021323 has 8 divisors (see below), whose sum is σ = 13524915911760. Its totient is φ = 13277539729440.

The previous prime is 13401221021273. The next prime is 13401221021359. The reversal of 13401221021323 is 32312012210431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13401221021323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401221621323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1414240 + ... + 5366797.

It is an arithmetic number, because the mean of its divisors is an integer number (1690614488970).

Almost surely, 213401221021323 is an apocalyptic number.

13401221021323 is a deficient number, since it is larger than the sum of its proper divisors (123694890437).

13401221021323 is a wasteful number, since it uses less digits than its factorization.

13401221021323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6799277.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13401221021323 its reverse (32312012210431), we get a palindrome (45713233231754).

The spelling of 13401221021323 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-one thousand, three hundred twenty-three".

Divisors: 1 109 18131 1976279 6781037 739133033 122946981847 13401221021323