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134012211203 = 1319951802169
BaseRepresentation
bin111110011001111000…
…0000001000000000011
3110210220112121200200202
41330303300001000003
54143424111224303
6141321522435415
712452643000053
oct1746360010003
9423815550622
10134012211203
115191a443862
1221b80502b6b
13c8391b03c0
1466b42bb563
1537451ebc88
hex1f33c01003

134012211203 has 8 divisors (see below), whose sum is σ = 145046076000. Its totient is φ = 123081951168.

The previous prime is 134012211167. The next prime is 134012211253. The reversal of 134012211203 is 302112210431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134012211203 - 228 = 133743775747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134012211253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25898498 + ... + 25903671.

It is an arithmetic number, because the mean of its divisors is an integer number (18130759500).

Almost surely, 2134012211203 is an apocalyptic number.

134012211203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

134012211203 is a deficient number, since it is larger than the sum of its proper divisors (11033864797).

134012211203 is a wasteful number, since it uses less digits than its factorization.

134012211203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51802381.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 134012211203 its reverse (302112210431), we get a palindrome (436124421634).

The spelling of 134012211203 in words is "one hundred thirty-four billion, twelve million, two hundred eleven thousand, two hundred three".

Divisors: 1 13 199 2587 51802169 673428197 10308631631 134012211203