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13401224354 = 271396886549
BaseRepresentation
bin11000111101100011…
…00111010010100010
31021120221202201210202
430132301213102202
5204421203134404
610053442425202
7653044345640
oct143661472242
937527681722
1013401224354
115757707231
122720062202
13135755166b
14911b6c190
155367a821e
hex31ec674a2

13401224354 has 16 divisors (see below), whose sum is σ = 23138808000. Its totient is φ = 5702061744.

The previous prime is 13401224341. The next prime is 13401224359. The reversal of 13401224354 is 45342210431.

13401224354 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13401224359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3441329 + ... + 3445220.

It is an arithmetic number, because the mean of its divisors is an integer number (1446175500).

Almost surely, 213401224354 is an apocalyptic number.

13401224354 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13401224354 is a deficient number, since it is larger than the sum of its proper divisors (9737583646).

13401224354 is a wasteful number, since it uses less digits than its factorization.

13401224354 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6886697.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13401224354 its reverse (45342210431), we get a palindrome (58743434785).

The spelling of 13401224354 in words is "thirteen billion, four hundred one million, two hundred twenty-four thousand, three hundred fifty-four".

Divisors: 1 2 7 14 139 278 973 1946 6886549 13773098 48205843 96411686 957230311 1914460622 6700612177 13401224354