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134012431532335 = 5191140327153437
BaseRepresentation
bin11110011110001000110011…
…011000001000000100101111
3122120111110111202211021010111
4132132020303120020010233
5120031124424433013320
61153004243334520451
740141035661043236
oct3636106330100457
9576443452737114
10134012431532335
11397783979a3064
1213044610206127
1359a1419a472c5
14251434456bb1d
151075e86b15a5a
hex79e23360812f

134012431532335 has 8 divisors (see below), whose sum is σ = 161656880760576. Its totient is φ = 106648636611360.

The previous prime is 134012431532327. The next prime is 134012431532377. The reversal of 134012431532335 is 533235134210431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 134012431532335 - 23 = 134012431532327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70163575764 + ... + 70163577673.

It is an arithmetic number, because the mean of its divisors is an integer number (20207110095072).

Almost surely, 2134012431532335 is an apocalyptic number.

134012431532335 is a deficient number, since it is larger than the sum of its proper divisors (27644449228241).

134012431532335 is a wasteful number, since it uses less digits than its factorization.

134012431532335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140327153633.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 134012431532335 its reverse (533235134210431), we get a palindrome (667247565742766).

The spelling of 134012431532335 in words is "one hundred thirty-four trillion, twelve billion, four hundred thirty-one million, five hundred thirty-two thousand, three hundred thirty-five".

Divisors: 1 5 191 955 140327153437 701635767185 26802486306467 134012431532335