13401244233101 has 4 divisors (see below), whose sum is σ = 13450695319104. Its totient is φ = 13351793147100.

The previous prime is 13401244233007. The next prime is 13401244233127. The reversal of 13401244233101 is 10133244210431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401244233101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401244235101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24725542595 + ... + 24725543136.

It is an arithmetic number, because the mean of its divisors is an integer number (3362673829776).

Almost surely, 2^{13401244233101} is an apocalyptic number.

It is an amenable number.

13401244233101 is a deficient number, since it is larger than the sum of its proper divisors (49451086003).

13401244233101 is an equidigital number, since it uses as much as digits as its factorization.

13401244233101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49451086002.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13401244233101 its reverse (10133244210431), we get a palindrome (23534488443532).

The spelling of 13401244233101 in words is "thirteen trillion, four hundred one billion, two hundred forty-four million, two hundred thirty-three thousand, one hundred one".