Base | Representation |
---|---|
bin | 10011100000000110000… |
… | …010011111010001100001 |
3 | 11202010010001010011121212 |
4 | 103200012002133101201 |
5 | 133424042031041113 |
6 | 2503351524355505 |
7 | 165551461334120 |
oct | 23400602372141 |
9 | 4663101104555 |
10 | 1340131112033 |
11 | 47738a09168a |
12 | 197887245b95 |
13 | 994b239468c |
14 | 48c11325ab7 |
15 | 24cd71aa0a8 |
hex | 1380609f461 |
1340131112033 has 16 divisors (see below), whose sum is σ = 1540221621120. Its totient is φ = 1142202902400.
The previous prime is 1340131111997. The next prime is 1340131112041. The reversal of 1340131112033 is 3302111310431.
It is not a de Polignac number, because 1340131112033 - 212 = 1340131107937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1340131112083) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11549258 + ... + 11664716.
It is an arithmetic number, because the mean of its divisors is an integer number (96263851320).
Almost surely, 21340131112033 is an apocalyptic number.
It is an amenable number.
1340131112033 is a deficient number, since it is larger than the sum of its proper divisors (200090509087).
1340131112033 is a wasteful number, since it uses less digits than its factorization.
1340131112033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124808.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1340131112033 its reverse (3302111310431), we get a palindrome (4642242422464).
The spelling of 1340131112033 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, one hundred twelve thousand, thirty-three".
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