1340131112041 has 2 divisors, whose sum is σ = 1340131112042. Its totient is φ = 1340131112040.

The previous prime is 1340131111997. The next prime is 1340131112081. The reversal of 1340131112041 is 1402111310431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 985296449641 + 354834662400 = 992621^2 + 595680^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340131112041 - 2²⁵ = 1340097557609 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340131112081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065556020 + 670065556021.

It is an arithmetic number, because the mean of its divisors is an integer number (670065556021).

Almost surely, 2^{1340131112041} is an apocalyptic number.

It is an amenable number.

1340131112041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340131112041 is an equidigital number, since it uses as much as digits as its factorization.

1340131112041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1340131112041 its reverse (1402111310431), we get a palindrome (2742242422472).

The spelling of 1340131112041 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, one hundred twelve thousand, forty-one".