13401312553 has 4 divisors (see below), whose sum is σ = 13402045188. Its totient is φ = 13400579920.

The previous prime is 13401312539. The next prime is 13401312571. The reversal of 13401312553 is 35521310431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35521310431 = 59 ⋅602056109.

It can be written as a sum of positive squares in 2 ways, for example, as 10952250409 + 2449062144 = 104653^2 + 49488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401312553 is a prime.

It is a super-3 number, since 3×13401312553³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401315553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338158 + ... + 375703.

It is an arithmetic number, because the mean of its divisors is an integer number (3350511297).

Almost surely, 2^13401312553 is an apocalyptic number.

It is an amenable number.

13401312553 is a deficient number, since it is larger than the sum of its proper divisors (732635).

13401312553 is an equidigital number, since it uses as much as digits as its factorization.

13401312553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 732634.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 13401312553 its reverse (35521310431), we get a palindrome (48922622984).

The spelling of 13401312553 in words is "thirteen billion, four hundred one million, three hundred twelve thousand, five hundred fifty-three".