Search a number
-
+
134013201301 = 791512092093
BaseRepresentation
bin111110011001111001…
…1110010101110010101
3110210220121110222212001
41330303303302232111
54143424334420201
6141321555555301
712452654262460
oct1746363625625
9423817428761
10134013201301
115191aa5a721
1221b808bbb31
13c839468c65
1466b44982d7
153745345301
hex1f33cf2b95

134013201301 has 8 divisors (see below), whose sum is σ = 153174754304. Its totient is φ = 114855850800.

The previous prime is 134013201263. The next prime is 134013201307. The reversal of 134013201301 is 103102310431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134013201301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134013201307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 981990 + ... + 1110103.

It is an arithmetic number, because the mean of its divisors is an integer number (19146844288).

Almost surely, 2134013201301 is an apocalyptic number.

It is an amenable number.

134013201301 is a deficient number, since it is larger than the sum of its proper divisors (19161553003).

134013201301 is an equidigital number, since it uses as much as digits as its factorization.

134013201301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2101251.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 134013201301 its reverse (103102310431), we get a palindrome (237115511732).

The spelling of 134013201301 in words is "one hundred thirty-four billion, thirteen million, two hundred one thousand, three hundred one".

Divisors: 1 7 9151 64057 2092093 14644651 19144743043 134013201301