Base | Representation |
---|---|
bin | 11000111101100011… |
… | …11111101001011001 |
3 | 1021120221221210122211 |
4 | 30132301333221121 |
5 | 204421214332441 |
6 | 10053444515121 |
7 | 653045242543 |
oct | 143661775131 |
9 | 37527853584 |
10 | 13401324121 |
11 | 5757775189 |
12 | 27200abaa1 |
13 | 1357587bb3 |
14 | 911b96693 |
15 | 5367c7a81 |
hex | 31ec7fa59 |
13401324121 has 8 divisors (see below), whose sum is σ = 13604591360. Its totient is φ = 13198152528.
The previous prime is 13401324109. The next prime is 13401324127. The reversal of 13401324121 is 12142310431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13401324121 - 29 = 13401323609 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13401324092 and 13401324101.
It is not an unprimeable number, because it can be changed into a prime (13401324127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 289255 + ... + 332371.
It is an arithmetic number, because the mean of its divisors is an integer number (1700573920).
Almost surely, 213401324121 is an apocalyptic number.
It is an amenable number.
13401324121 is a deficient number, since it is larger than the sum of its proper divisors (203267239).
13401324121 is an equidigital number, since it uses as much as digits as its factorization.
13401324121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47823.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13401324121 its reverse (12142310431), we get a palindrome (25543634552).
The spelling of 13401324121 in words is "thirteen billion, four hundred one million, three hundred twenty-four thousand, one hundred twenty-one".
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