Base | Representation |
---|---|
bin | 11000111101100011… |
… | …11111101001011111 |
3 | 1021120221221210200001 |
4 | 30132301333221133 |
5 | 204421214333002 |
6 | 10053444515131 |
7 | 653045242552 |
oct | 143661775137 |
9 | 37527853601 |
10 | 13401324127 |
11 | 5757775194 |
12 | 27200abaa7 |
13 | 1357587bb9 |
14 | 911b96699 |
15 | 5367c7a87 |
hex | 31ec7fa5f |
13401324127 has 2 divisors, whose sum is σ = 13401324128. Its totient is φ = 13401324126.
The previous prime is 13401324109. The next prime is 13401324193. The reversal of 13401324127 is 72142310431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13401324127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13401324095 and 13401324104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13401324197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700662063 + 6700662064.
It is an arithmetic number, because the mean of its divisors is an integer number (6700662064).
Almost surely, 213401324127 is an apocalyptic number.
13401324127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401324127 is an equidigital number, since it uses as much as digits as its factorization.
13401324127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 13401324127 its reverse (72142310431), we get a palindrome (85543634558).
The spelling of 13401324127 in words is "thirteen billion, four hundred one million, three hundred twenty-four thousand, one hundred twenty-seven".
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