Base | Representation |
---|---|
bin | 1100001100000011111110… |
… | …1111100101111111011001 |
3 | 1202110011021100002020121121 |
4 | 3003000333233211333121 |
5 | 3224032000023421010 |
6 | 44300300405005241 |
7 | 2552134243266433 |
oct | 303007757457731 |
9 | 52404240066547 |
10 | 13401367404505 |
11 | 42a7540588363 |
12 | 16053369b3821 |
13 | 7629886a1a42 |
14 | 3448b5a53653 |
15 | 1839011373da |
hex | c303fbe5fd9 |
13401367404505 has 4 divisors (see below), whose sum is σ = 16081640885412. Its totient is φ = 10721093923600.
The previous prime is 13401367404497. The next prime is 13401367404527. The reversal of 13401367404505 is 50540476310431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1646014586841 + 11755352817664 = 1282971^2 + 3428608^2 .
It is not a de Polignac number, because 13401367404505 - 23 = 13401367404497 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340136740446 + ... + 1340136740455.
It is an arithmetic number, because the mean of its divisors is an integer number (4020410221353).
Almost surely, 213401367404505 is an apocalyptic number.
It is an amenable number.
13401367404505 is a deficient number, since it is larger than the sum of its proper divisors (2680273480907).
13401367404505 is an equidigital number, since it uses as much as digits as its factorization.
13401367404505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2680273480906.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 13401367404505 in words is "thirteen trillion, four hundred one billion, three hundred sixty-seven million, four hundred four thousand, five hundred five".
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