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13401403034098 = 26700701517049
BaseRepresentation
bin1100001100000100000111…
…0111100000100111110010
31202110011100211010102020011
43003001001313200213302
53224032033134042343
644300304120405134
72552135155163002
oct303010167404762
952404324112204
1013401403034098
1142a7559703402
1216053469167aa
13762992b98241
143448ba68a002
1518390432429d
hexc3041de09f2

13401403034098 has 4 divisors (see below), whose sum is σ = 20102104551150. Its totient is φ = 6700701517048.

The previous prime is 13401403034023. The next prime is 13401403034119. The reversal of 13401403034098 is 89043030410431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10119352674649 + 3282050359449 = 3181093^2 + 1811643^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13401403034098.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350350758523 + ... + 3350350758526.

Almost surely, 213401403034098 is an apocalyptic number.

13401403034098 is a deficient number, since it is larger than the sum of its proper divisors (6700701517052).

13401403034098 is an equidigital number, since it uses as much as digits as its factorization.

13401403034098 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6700701517051.

The product of its (nonzero) digits is 124416, while the sum is 40.

The spelling of 13401403034098 in words is "thirteen trillion, four hundred one billion, four hundred three million, thirty-four thousand, ninety-eight".

Divisors: 1 2 6700701517049 13401403034098