13401403040021 has 4 divisors (see below), whose sum is σ = 13728266528844. Its totient is φ = 13074539551200.

The previous prime is 13401403040009. The next prime is 13401403040059. The reversal of 13401403040021 is 12004030410431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8118162879121 + 5283240160900 = 2849239^2 + 2298530^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401403040021 - 2²² = 13401398845717 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401403042021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163431744350 + ... + 163431744431.

It is an arithmetic number, because the mean of its divisors is an integer number (3432066632211).

Almost surely, 2^{13401403040021} is an apocalyptic number.

It is an amenable number.

13401403040021 is a deficient number, since it is larger than the sum of its proper divisors (326863488823).

13401403040021 is an equidigital number, since it uses as much as digits as its factorization.

13401403040021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 326863488822.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13401403040021 its reverse (12004030410431), we get a palindrome (25405433450452).

The spelling of 13401403040021 in words is "thirteen trillion, four hundred one billion, four hundred three million, forty thousand, twenty-one".