13401411103 has 8 divisors (see below), whose sum is σ = 13502374848. Its totient is φ = 13300493184.

The previous prime is 13401411097. The next prime is 13401411109. The reversal of 13401411103 is 30111410431.

It is an interprime number because it is at equal distance from previous prime (13401411097) and next prime (13401411109).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401411103 - 2⁵ = 13401411071 is a prime.

It is a super-2 number, since 2×13401411103² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401411109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 778275 + ... + 795307.

It is an arithmetic number, because the mean of its divisors is an integer number (1687796856).

Almost surely, 2^13401411103 is an apocalyptic number.

13401411103 is a deficient number, since it is larger than the sum of its proper divisors (100963745).

13401411103 is a wasteful number, since it uses less digits than its factorization.

13401411103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22913.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13401411103 its reverse (30111410431), we get a palindrome (43512821534).

The spelling of 13401411103 in words is "thirteen billion, four hundred one million, four hundred eleven thousand, one hundred three".