Base | Representation |
---|---|
bin | 11000111101100100… |
… | …11100110001010011 |
3 | 1021120222011212021222 |
4 | 30132302130301103 |
5 | 204421232142121 |
6 | 10053451235255 |
7 | 653046250406 |
oct | 143662346123 |
9 | 37528155258 |
10 | 13401443411 |
11 | 5757846874 |
12 | 2720148b2b |
13 | 13575ca295 |
14 | 911bc7d3d |
15 | 5367ed0ab |
hex | 31ec9cc53 |
13401443411 has 4 divisors (see below), whose sum is σ = 13436803800. Its totient is φ = 13366083024.
The previous prime is 13401443399. The next prime is 13401443453. The reversal of 13401443411 is 11434410431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11434410431 = 14447 ⋅791473.
It is a cyclic number.
It is not a de Polignac number, because 13401443411 - 218 = 13401181267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13401443911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17679626 + ... + 17680383.
It is an arithmetic number, because the mean of its divisors is an integer number (3359200950).
Almost surely, 213401443411 is an apocalyptic number.
13401443411 is a deficient number, since it is larger than the sum of its proper divisors (35360389).
13401443411 is an equidigital number, since it uses as much as digits as its factorization.
13401443411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35360388.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 13401443411 its reverse (11434410431), we get a palindrome (24835853842).
The spelling of 13401443411 in words is "thirteen billion, four hundred one million, four hundred forty-three thousand, four hundred eleven".
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