134015021 has 4 divisors (see below), whose sum is σ = 153160032. Its totient is φ = 114870012.

The previous prime is 134015009. The next prime is 134015033. The reversal of 134015021 is 120510431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 120510431 = 5477 ⋅22003.

It is an interprime number because it is at equal distance from previous prime (134015009) and next prime (134015033).

It is a cyclic number.

It is not a de Polignac number, because 134015021 - 2⁶ = 134014957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134015071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9572495 + ... + 9572508.

It is an arithmetic number, because the mean of its divisors is an integer number (38290008).

Almost surely, 2^134015021 is an apocalyptic number.

It is an amenable number.

134015021 is a deficient number, since it is larger than the sum of its proper divisors (19145011).

134015021 is an equidigital number, since it uses as much as digits as its factorization.

134015021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19145010.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 134015021 is about 11576.4856929899. The cubic root of 134015021 is about 511.7421148502.

Adding to 134015021 its reverse (120510431), we get a palindrome (254525452).

It can be divided in two parts, 1340 and 15021, that added together give a palindrome (16361).

The spelling of 134015021 in words is "one hundred thirty-four million, fifteen thousand, twenty-one".