1340151545001 has 4 divisors (see below), whose sum is σ = 1786868726672. Its totient is φ = 893434363332.

The previous prime is 1340151544993. The next prime is 1340151545071. The reversal of 1340151545001 is 1005451510431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1340151545001 - 2³ = 1340151544993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340151545001.

It is not an unprimeable number, because it can be changed into a prime (1340151545071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223358590831 + ... + 223358590836.

It is an arithmetic number, because the mean of its divisors is an integer number (446717181668).

Almost surely, 2^{1340151545001} is an apocalyptic number.

It is an amenable number.

1340151545001 is a deficient number, since it is larger than the sum of its proper divisors (446717181671).

1340151545001 is an equidigital number, since it uses as much as digits as its factorization.

1340151545001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 446717181670.

The product of its (nonzero) digits is 6000, while the sum is 30.

The spelling of 1340151545001 in words is "one trillion, three hundred forty billion, one hundred fifty-one million, five hundred forty-five thousand, one".