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1340154103 = 4676434463
BaseRepresentation
bin100111111100001…
…0010000011110111
310110101201212211011
41033320102003313
510221034412403
6340552053051
745132056551
oct11770220367
93411655734
101340154103
11628533682
12314994187
131848569c2
14c9db44d1
157c9c2a6d
hex4fe120f7

1340154103 has 8 divisors (see below), whose sum is σ = 1345413888. Its totient is φ = 1334905464.

The previous prime is 1340154077. The next prime is 1340154107. The reversal of 1340154103 is 3014510431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340154103 - 25 = 1340154071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340154107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 298050 + ... + 302512.

It is an arithmetic number, because the mean of its divisors is an integer number (168176736).

Almost surely, 21340154103 is an apocalyptic number.

1340154103 is a deficient number, since it is larger than the sum of its proper divisors (5259785).

1340154103 is an equidigital number, since it uses as much as digits as its factorization.

1340154103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5573.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 1340154103 is about 36608.1152615100. The cubic root of 1340154103 is about 1102.5160321471.

Adding to 1340154103 its reverse (3014510431), we get a palindrome (4354664534).

The spelling of 1340154103 in words is "one billion, three hundred forty million, one hundred fifty-four thousand, one hundred three".

Divisors: 1 467 643 4463 300281 2084221 2869709 1340154103