13401643065845 has 4 divisors (see below), whose sum is σ = 16081971679020. Its totient is φ = 10721314452672.

The previous prime is 13401643065841. The next prime is 13401643065907. The reversal of 13401643065845 is 54856034610431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4809674451409 + 8591968614436 = 2193097^2 + 2931206^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401643065845 - 2² = 13401643065841 is a prime.

It is a super-2 number, since 2×13401643065845² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13401643065793 and 13401643065802.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401643065841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340164306580 + ... + 1340164306589.

It is an arithmetic number, because the mean of its divisors is an integer number (4020492919755).

Almost surely, 2^{13401643065845} is an apocalyptic number.

It is an amenable number.

13401643065845 is a deficient number, since it is larger than the sum of its proper divisors (2680328613175).

13401643065845 is an equidigital number, since it uses as much as digits as its factorization.

13401643065845 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2680328613174.

The product of its (nonzero) digits is 4147200, while the sum is 50.

The spelling of 13401643065845 in words is "thirteen trillion, four hundred one billion, six hundred forty-three million, sixty-five thousand, eight hundred forty-five".