13402002223 has 4 divisors (see below), whose sum is σ = 13728880368. Its totient is φ = 13075124080.

The previous prime is 13402002221. The next prime is 13402002269. The reversal of 13402002223 is 32220020431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13402002223 - 2¹ = 13402002221 is a prime.

It is a super-2 number, since 2×13402002223² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13402002223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402002221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163439011 + ... + 163439092.

It is an arithmetic number, because the mean of its divisors is an integer number (3432220092).

Almost surely, 2^13402002223 is an apocalyptic number.

13402002223 is a deficient number, since it is larger than the sum of its proper divisors (326878145).

13402002223 is an equidigital number, since it uses as much as digits as its factorization.

13402002223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 326878144.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 13402002223 its reverse (32220020431), we get a palindrome (45622022654).

The spelling of 13402002223 in words is "thirteen billion, four hundred two million, two thousand, two hundred twenty-three".