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1340200321004 = 22335050080251
BaseRepresentation
bin10011100000001010001…
…010011111111111101100
311202010021212100100111002
4103200022022133333230
5133424212240233004
62503402440015432
7165553261524416
oct23401212377754
94663255310432
101340200321004
11477415162386
121978a6461578
13994c381712c
1448c1a5bd9b6
1524cdd2cb61e
hex1380a29ffec

1340200321004 has 6 divisors (see below), whose sum is σ = 2345350561764. Its totient is φ = 670100160500.

The previous prime is 1340200320947. The next prime is 1340200321007. The reversal of 1340200321004 is 4001230020431.

It is a super-2 number, since 2×13402003210042 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340200321007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167525040122 + ... + 167525040129.

It is an arithmetic number, because the mean of its divisors is an integer number (390891760294).

Almost surely, 21340200321004 is an apocalyptic number.

It is an amenable number.

1340200321004 is a deficient number, since it is larger than the sum of its proper divisors (1005150240760).

1340200321004 is a wasteful number, since it uses less digits than its factorization.

1340200321004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335050080255 (or 335050080253 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 1340200321004 its reverse (4001230020431), we get a palindrome (5341430341435).

The spelling of 1340200321004 in words is "one trillion, three hundred forty billion, two hundred million, three hundred twenty-one thousand, four".

Divisors: 1 2 4 335050080251 670100160502 1340200321004