13402004071013 has 4 divisors (see below), whose sum is σ = 13409675511840. Its totient is φ = 13394332630188.

The previous prime is 13402004071009. The next prime is 13402004071019. The reversal of 13402004071013 is 31017040020431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13402004071013 - 2² = 13402004071009 is a prime.

It is a super-2 number, since 2×13402004071013² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402004071019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3835717793 + ... + 3835721286.

It is an arithmetic number, because the mean of its divisors is an integer number (3352418877960).

Almost surely, 2^{13402004071013} is an apocalyptic number.

It is an amenable number.

13402004071013 is a deficient number, since it is larger than the sum of its proper divisors (7671440827).

13402004071013 is an equidigital number, since it uses as much as digits as its factorization.

13402004071013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7671440826.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 13402004071013 its reverse (31017040020431), we get a palindrome (44419044091444).

The spelling of 13402004071013 in words is "thirteen trillion, four hundred two billion, four million, seventy-one thousand, thirteen".