Base | Representation |
---|---|
bin | 11000111101101001… |
… | …00111001000100011 |
3 | 1021121000020122201012 |
4 | 30132310213020203 |
5 | 204421403311042 |
6 | 10053511331135 |
7 | 653054130611 |
oct | 143664471043 |
9 | 37530218635 |
10 | 13402010147 |
11 | 57580a3649 |
12 | 2720380aab |
13 | 1357768226 |
14 | 911cd46b1 |
15 | 5368b0e82 |
hex | 31ed27223 |
13402010147 has 4 divisors (see below), whose sum is σ = 13402411320. Its totient is φ = 13401608976.
The previous prime is 13402010143. The next prime is 13402010227. The reversal of 13402010147 is 74101020431.
It is a happy number.
13402010147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74101020431 = 23 ⋅3221783497.
It is a cyclic number.
It is not a de Polignac number, because 13402010147 - 22 = 13402010143 is a prime.
It is a super-2 number, since 2×134020101472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13402010143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145418 + ... + 218975.
It is an arithmetic number, because the mean of its divisors is an integer number (3350602830).
Almost surely, 213402010147 is an apocalyptic number.
13402010147 is a deficient number, since it is larger than the sum of its proper divisors (401173).
13402010147 is an equidigital number, since it uses as much as digits as its factorization.
13402010147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401172.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 13402010147 its reverse (74101020431), we get a palindrome (87503030578).
The spelling of 13402010147 in words is "thirteen billion, four hundred two million, ten thousand, one hundred forty-seven".
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