1340202121113 has 64 divisors (see below), whose sum is σ = 1955624815872. Its totient is φ = 812957368320.

The previous prime is 1340202121091. The next prime is 1340202121129. The reversal of 1340202121113 is 3111212020431.

It is not a de Polignac number, because 1340202121113 - 2²⁰ = 1340201072537 is a prime.

It is a super-2 number, since 2×1340202121113² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340202121113.

It is not an unprimeable number, because it can be changed into a prime (1340202121913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 397330695 + ... + 397334067.

It is an arithmetic number, because the mean of its divisors is an integer number (30556637748).

Almost surely, 2^{1340202121113} is an apocalyptic number.

It is an amenable number.

1340202121113 is a deficient number, since it is larger than the sum of its proper divisors (615422694759).

1340202121113 is a wasteful number, since it uses less digits than its factorization.

1340202121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4714.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1340202121113 its reverse (3111212020431), we get a palindrome (4451414141544).

The spelling of 1340202121113 in words is "one trillion, three hundred forty billion, two hundred two million, one hundred twenty-one thousand, one hundred thirteen".