13402117 has 4 divisors (see below), whose sum is σ = 13411840. Its totient is φ = 13392396.

The previous prime is 13402099. The next prime is 13402133. The reversal of 13402117 is 71120431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13402117 - 2⁷ = 13401989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402094 and 13402103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2367 + ... + 5692.

It is an arithmetic number, because the mean of its divisors is an integer number (3352960).

Almost surely, 2^13402117 is an apocalyptic number.

It is an amenable number.

13402117 is a deficient number, since it is larger than the sum of its proper divisors (9723).

13402117 is an equidigital number, since it uses as much as digits as its factorization.

13402117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9722.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 13402117 is about 3660.8901922893. The cubic root of 13402117 is about 237.5332813932.

Adding to 13402117 its reverse (71120431), we get a palindrome (84522548).

The spelling of 13402117 in words is "thirteen million, four hundred two thousand, one hundred seventeen".