Base | Representation |
---|---|
bin | 1100001100000111001111… |
… | …1000011100100010001111 |
3 | 1202110020112022001102112202 |
4 | 3003001303320130202033 |
5 | 3224040242441442203 |
6 | 44300523253352115 |
7 | 2552165024362532 |
oct | 303016370344217 |
9 | 52406468042482 |
10 | 13402242140303 |
11 | 42a794a324305 |
12 | 160553b93863b |
13 | 762a97990ba3 |
14 | 344959cb4a19 |
15 | 183952d23388 |
hex | c3073e1c88f |
13402242140303 has 4 divisors (see below), whose sum is σ = 13402322630808. Its totient is φ = 13402161649800.
The previous prime is 13402242140279. The next prime is 13402242140311. The reversal of 13402242140303 is 30304124220431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13402242140303 - 28 = 13402242140047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13402242140323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39994973 + ... + 40328678.
It is an arithmetic number, because the mean of its divisors is an integer number (3350580657702).
Almost surely, 213402242140303 is an apocalyptic number.
13402242140303 is a deficient number, since it is larger than the sum of its proper divisors (80490505).
13402242140303 is an equidigital number, since it uses as much as digits as its factorization.
13402242140303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80490504.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13402242140303 its reverse (30304124220431), we get a palindrome (43706366360734).
The spelling of 13402242140303 in words is "thirteen trillion, four hundred two billion, two hundred forty-two million, one hundred forty thousand, three hundred three".
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