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13402251035 = 52680450207
BaseRepresentation
bin11000111101101011…
…00001111100011011
31021121000200220010222
430132311201330123
5204421434013120
610053520430255
7653056153115
oct143665417433
937530626128
1013402251035
115758248628
12272047838b
131357820a74
14911d583b5
1553690c525
hex31ed61f1b

13402251035 has 4 divisors (see below), whose sum is σ = 16082701248. Its totient is φ = 10721800824.

The previous prime is 13402251017. The next prime is 13402251047. The reversal of 13402251035 is 53015220431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13402251035 - 26 = 13402250971 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402250995 and 13402251013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340225099 + ... + 1340225108.

It is an arithmetic number, because the mean of its divisors is an integer number (4020675312).

Almost surely, 213402251035 is an apocalyptic number.

13402251035 is a deficient number, since it is larger than the sum of its proper divisors (2680450213).

13402251035 is an equidigital number, since it uses as much as digits as its factorization.

13402251035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2680450212.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 13402251035 its reverse (53015220431), we get a palindrome (66417471466).

The spelling of 13402251035 in words is "thirteen billion, four hundred two million, two hundred fifty-one thousand, thirty-five".

Divisors: 1 5 2680450207 13402251035