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1340231412332 = 221279126194813
BaseRepresentation
bin10011100000001100000…
…001000110101001101100
311202010101000211221202202
4103200030001012221230
5133424243220143312
62503405510241032
7165554120016611
oct23401401065154
94663330757682
101340231412332
1147743076879a
121978b4956178
13994ca0b1a77
1448c20794508
1524ce0dbd9c2
hex1380c046a6c

1340231412332 has 12 divisors (see below), whose sum is σ = 2345588424816. Its totient is φ = 670063290960.

The previous prime is 1340231412301. The next prime is 1340231412347. The reversal of 1340231412332 is 2332141320431.

It is a junction number, because it is equal to n+sod(n) for n = 1340231412295 and 1340231412304.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13046243 + ... + 13148570.

It is an arithmetic number, because the mean of its divisors is an integer number (195465702068).

Almost surely, 21340231412332 is an apocalyptic number.

It is an amenable number.

1340231412332 is a deficient number, since it is larger than the sum of its proper divisors (1005357012484).

1340231412332 is a wasteful number, since it uses less digits than its factorization.

1340231412332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26207608 (or 26207606 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1340231412332 its reverse (2332141320431), we get a palindrome (3672372732763).

The spelling of 1340231412332 in words is "one trillion, three hundred forty billion, two hundred thirty-one million, four hundred twelve thousand, three hundred thirty-two".

Divisors: 1 2 4 12791 25582 51164 26194813 52389626 104779252 335057853083 670115706166 1340231412332