13402331044403 has 8 divisors (see below), whose sum is σ = 15317298000480. Its totient is φ = 11487451147200.

The previous prime is 13402331044393. The next prime is 13402331044439. The reversal of 13402331044403 is 30444013320431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-13402331044403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13402331044403.

It is not an unprimeable number, because it can be changed into a prime (13402331041403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21434498 + ... + 22050903.

It is an arithmetic number, because the mean of its divisors is an integer number (1914662250060).

Almost surely, 2^{13402331044403} is an apocalyptic number.

13402331044403 is a deficient number, since it is larger than the sum of its proper divisors (1914966956077).

13402331044403 is an equidigital number, since it uses as much as digits as its factorization.

13402331044403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43529437.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 13402331044403 its reverse (30444013320431), we get a palindrome (43846344364834).

The spelling of 13402331044403 in words is "thirteen trillion, four hundred two billion, three hundred thirty-one million, forty-four thousand, four hundred three".