Base | Representation |
---|---|
bin | 10011100000001100100… |
… | …110000100001011110011 |
3 | 11202010101201002012212212 |
4 | 103200030212010023303 |
5 | 133424303210222210 |
6 | 2503410454042335 |
7 | 165554265253226 |
oct | 23401446041363 |
9 | 4663351065785 |
10 | 1340241101555 |
11 | 477436186414 |
12 | 1978b80493ab |
13 | 994cc0c5035 |
14 | 48c21b975bd |
15 | 24ce1b84805 |
hex | 1380c9842f3 |
1340241101555 has 32 divisors (see below), whose sum is σ = 1734606619200. Its totient is φ = 990770227200.
The previous prime is 1340241101527. The next prime is 1340241101597. The reversal of 1340241101555 is 5551011420431.
It is not a de Polignac number, because 1340241101555 - 26 = 1340241101491 is a prime.
It is a super-3 number, since 3×13402411015553 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19007465 + ... + 19077845.
It is an arithmetic number, because the mean of its divisors is an integer number (54206456850).
Almost surely, 21340241101555 is an apocalyptic number.
1340241101555 is a deficient number, since it is larger than the sum of its proper divisors (394365517645).
1340241101555 is a wasteful number, since it uses less digits than its factorization.
1340241101555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75335.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 1340241101555 its reverse (5551011420431), we get a palindrome (6891252521986).
The spelling of 1340241101555 in words is "one trillion, three hundred forty billion, two hundred forty-one million, one hundred one thousand, five hundred fifty-five".
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