1340241313 has 4 divisors (see below), whose sum is σ = 1340851888. Its totient is φ = 1339630740.

The previous prime is 1340241311. The next prime is 1340241341. The reversal of 1340241313 is 3131420431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3131420431 = 83 ⋅37727957.

It is a cyclic number.

It is not a de Polignac number, because 1340241313 - 2¹ = 1340241311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340241311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301983 + ... + 306388.

It is an arithmetic number, because the mean of its divisors is an integer number (335212972).

Almost surely, 2^1340241313 is an apocalyptic number.

It is an amenable number.

1340241313 is a deficient number, since it is larger than the sum of its proper divisors (610575).

1340241313 is an equidigital number, since it uses as much as digits as its factorization.

1340241313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 610574.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 1340241313 is about 36609.3063714679. The cubic root of 1340241313 is about 1102.5399468937.

Adding to 1340241313 its reverse (3131420431), we get a palindrome (4471661744).

The spelling of 1340241313 in words is "one billion, three hundred forty million, two hundred forty-one thousand, three hundred thirteen".