1340241311 has 2 divisors, whose sum is σ = 1340241312. Its totient is φ = 1340241310.

The previous prime is 1340241281. The next prime is 1340241341. The reversal of 1340241311 is 1131420431.

It is a balanced prime because it is at equal distance from previous prime (1340241281) and next prime (1340241341).

It is a cyclic number.

It is not a de Polignac number, because 1340241311 - 2¹⁰ = 1340240287 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340241341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670120655 + 670120656.

It is an arithmetic number, because the mean of its divisors is an integer number (670120656).

Almost surely, 2^1340241311 is an apocalyptic number.

1340241311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340241311 is an equidigital number, since it uses as much as digits as its factorization.

1340241311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1340241311 is about 36609.3063441524. The cubic root of 1340241311 is about 1102.5399463453.

Adding to 1340241311 its reverse (1131420431), we get a palindrome (2471661742).

The spelling of 1340241311 in words is "one billion, three hundred forty million, two hundred forty-one thousand, three hundred eleven".