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13402420122034 = 230222722172771
BaseRepresentation
bin1100001100000111111001…
…1111011001000110110010
31202110020222200221211120201
43003001332133121012302
53224041124022401114
644300553052225414
72552202315243646
oct303017637310662
952406880854521
1013402420122034
1142a7a30838649
12160558b46b26a
13762ac5809218
143449757a4c26
1518396377d874
hexc307e7d91b2

13402420122034 has 8 divisors (see below), whose sum is σ = 20103697608048. Its totient is φ = 6701187586020.

The previous prime is 13402420122023. The next prime is 13402420122053. The reversal of 13402420122034 is 43022102420431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13402420121993 and 13402420122011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10481932 + ... + 11690839.

It is an arithmetic number, because the mean of its divisors is an integer number (2512962201006).

Almost surely, 213402420122034 is an apocalyptic number.

13402420122034 is a deficient number, since it is larger than the sum of its proper divisors (6701277486014).

13402420122034 is a wasteful number, since it uses less digits than its factorization.

13402420122034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22475000.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 13402420122034 its reverse (43022102420431), we get a palindrome (56424522542465).

The spelling of 13402420122034 in words is "thirteen trillion, four hundred two billion, four hundred twenty million, one hundred twenty-two thousand, thirty-four".

Divisors: 1 2 302227 604454 22172771 44345542 6701210061017 13402420122034