Base | Representation |
---|---|
bin | 111110011010001111… |
… | …0100000111000110001 |
3 | 110210221101112222011201 |
4 | 1330310132200320301 |
5 | 4143440221303213 |
6 | 141323040011201 |
7 | 12453151415140 |
oct | 1746436407061 |
9 | 423841488151 |
10 | 134024400433 |
11 | 51926309800 |
12 | 21b84600b01 |
13 | c83b88a571 |
14 | 66b5b71757 |
15 | 37463086dd |
hex | 1f347a0e31 |
134024400433 has 24 divisors (see below), whose sum is σ = 169851273984. Its totient is φ = 103510323840.
The previous prime is 134024400287. The next prime is 134024400449. The reversal of 134024400433 is 334004420431.
It is not a de Polignac number, because 134024400433 - 213 = 134024392241 is a prime.
It is a super-2 number, since 2×1340244004332 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (134024400473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 604441 + ... + 795862.
It is an arithmetic number, because the mean of its divisors is an integer number (7077136416).
Almost surely, 2134024400433 is an apocalyptic number.
It is an amenable number.
134024400433 is a deficient number, since it is larger than the sum of its proper divisors (35826873551).
134024400433 is a wasteful number, since it uses less digits than its factorization.
134024400433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1400445 (or 1400434 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 134024400433 its reverse (334004420431), we get a palindrome (468028820864).
The spelling of 134024400433 in words is "one hundred thirty-four billion, twenty-four million, four hundred thousand, four hundred thirty-three".
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