13402444000335 has 16 divisors (see below), whose sum is σ = 23093441970144. Its totient is φ = 6598126276992.

The previous prime is 13402444000333. The next prime is 13402444000343. The reversal of 13402444000335 is 53300044420431.

It is not a de Polignac number, because 13402444000335 - 2¹ = 13402444000333 is a prime.

It is a super-2 number, since 2×13402444000335² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402444000296 and 13402444000305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402444000333) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34365240832 + ... + 34365241221.

It is an arithmetic number, because the mean of its divisors is an integer number (1443340123134).

Almost surely, 2^{13402444000335} is an apocalyptic number.

13402444000335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13402444000335 is a deficient number, since it is larger than the sum of its proper divisors (9690997969809).

13402444000335 is a wasteful number, since it uses less digits than its factorization.

13402444000335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68730482074.

The product of its (nonzero) digits is 69120, while the sum is 33.

Adding to 13402444000335 its reverse (53300044420431), we get a palindrome (66702488420766).

The spelling of 13402444000335 in words is "thirteen trillion, four hundred two billion, four hundred forty-four million, three hundred thirty-five", and thus it is an aban number.