134025125132401 has 4 divisors (see below), whose sum is σ = 134263180417392. Its totient is φ = 133787069847412.

The previous prime is 134025125132387. The next prime is 134025125132417. The reversal of 134025125132401 is 104231521520431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134025125132401 - 2⁵ = 134025125132369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134025125142401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119027641651 + ... + 119027642776.

It is an arithmetic number, because the mean of its divisors is an integer number (33565795104348).

Almost surely, 2^{134025125132401} is an apocalyptic number.

It is an amenable number.

134025125132401 is a deficient number, since it is larger than the sum of its proper divisors (238055284991).

134025125132401 is an equidigital number, since it uses as much as digits as its factorization.

134025125132401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238055284990.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 134025125132401 its reverse (104231521520431), we get a palindrome (238256646652832).

The spelling of 134025125132401 in words is "one hundred thirty-four trillion, twenty-five billion, one hundred twenty-five million, one hundred thirty-two thousand, four hundred one".