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13402545522511 = 73183596514007
BaseRepresentation
bin1100001100001000010111…
…1101110000011101001111
31202110021022102220211200211
43003002011331300131033
53224041403123210021
644301013332103251
72552205400160005
oct303020575603517
952407272824624
1013402545522511
1142a7a955a8902
121605605464b27
13762b157a42a2
143449882c8a75
1518396e79e3e1
hexc3085f7074f

13402545522511 has 4 divisors (see below), whose sum is σ = 13586142036592. Its totient is φ = 13218949008432.

The previous prime is 13402545522463. The next prime is 13402545522539. The reversal of 13402545522511 is 11522554520431.

13402545522511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13402545522511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402545522211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91798256931 + ... + 91798257076.

It is an arithmetic number, because the mean of its divisors is an integer number (3396535509148).

Almost surely, 213402545522511 is an apocalyptic number.

13402545522511 is a deficient number, since it is larger than the sum of its proper divisors (183596514081).

13402545522511 is an equidigital number, since it uses as much as digits as its factorization.

13402545522511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183596514080.

The product of its (nonzero) digits is 240000, while the sum is 40.

The spelling of 13402545522511 in words is "thirteen trillion, four hundred two billion, five hundred forty-five million, five hundred twenty-two thousand, five hundred eleven".

Divisors: 1 73 183596514007 13402545522511