Base | Representation |
---|---|
bin | 1100001100001010100000… |
… | …1110110100010101110011 |
3 | 1202110022210111200200002020 |
4 | 3003002220032310111303 |
5 | 3224044042311421321 |
6 | 44301150350122523 |
7 | 2552225550546414 |
oct | 303025016642563 |
9 | 52408714620066 |
10 | 13403120420211 |
11 | 42a8260070a75 |
12 | 1605745ab0443 |
13 | 762ba7921242 |
14 | 344a007b980b |
15 | 1839a4eae4c6 |
hex | c30a83b4573 |
13403120420211 has 4 divisors (see below), whose sum is σ = 17870827226952. Its totient is φ = 8935413613472.
The previous prime is 13403120420189. The next prime is 13403120420281. The reversal of 13403120420211 is 11202402130431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13403120420211 - 215 = 13403120387443 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13403120420281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233853403366 + ... + 2233853403371.
It is an arithmetic number, because the mean of its divisors is an integer number (4467706806738).
Almost surely, 213403120420211 is an apocalyptic number.
13403120420211 is a deficient number, since it is larger than the sum of its proper divisors (4467706806741).
13403120420211 is an equidigital number, since it uses as much as digits as its factorization.
13403120420211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4467706806740.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13403120420211 its reverse (11202402130431), we get a palindrome (24605522550642).
The spelling of 13403120420211 in words is "thirteen trillion, four hundred three billion, one hundred twenty million, four hundred twenty thousand, two hundred eleven".
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