134032124011241 has 4 divisors (see below), whose sum is σ = 134118097152000. Its totient is φ = 133946150870484.

The previous prime is 134032124011231. The next prime is 134032124011301. The reversal of 134032124011241 is 142110421230431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134032124011241 - 2¹⁰ = 134032124010217 is a prime.

It is a super-2 number, since 2×134032124011241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134032124011231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42986568041 + ... + 42986571158.

It is an arithmetic number, because the mean of its divisors is an integer number (33529524288000).

Almost surely, 2^{134032124011241} is an apocalyptic number.

It is an amenable number.

134032124011241 is a deficient number, since it is larger than the sum of its proper divisors (85973140759).

134032124011241 is an equidigital number, since it uses as much as digits as its factorization.

134032124011241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85973140758.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 134032124011241 its reverse (142110421230431), we get a palindrome (276142545241672).

The spelling of 134032124011241 in words is "one hundred thirty-four trillion, thirty-two billion, one hundred twenty-four million, eleven thousand, two hundred forty-one".