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134032124011301 is a prime number
BaseRepresentation
bin11110011110011011001001…
…001000111110001100100101
3122120120100100011200211211022
4132132123021020332030211
5120031440242221330201
61153021301401020525
740142333660254325
oct3636331110761445
9576510304624738
10134032124011301
1139785782880a6a
12130483a7184745
1359a32377bca19
142515291a83285
15107673a88941b
hex79e6c923e325

134032124011301 has 2 divisors, whose sum is σ = 134032124011302. Its totient is φ = 134032124011300.

The previous prime is 134032124011231. The next prime is 134032124011337. The reversal of 134032124011301 is 103110421230431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134031907156225 + 216855076 = 11577215^2 + 14726^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134032124011301 is a prime.

It is a super-2 number, since 2×1340321240113012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134032124011601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67016062005650 + 67016062005651.

It is an arithmetic number, because the mean of its divisors is an integer number (67016062005651).

Almost surely, 2134032124011301 is an apocalyptic number.

It is an amenable number.

134032124011301 is a deficient number, since it is larger than the sum of its proper divisors (1).

134032124011301 is an equidigital number, since it uses as much as digits as its factorization.

134032124011301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 134032124011301 its reverse (103110421230431), we get a palindrome (237142545241732).

The spelling of 134032124011301 in words is "one hundred thirty-four trillion, thirty-two billion, one hundred twenty-four million, eleven thousand, three hundred one".