Base | Representation |
---|---|
bin | 10011100000010001011… |
… | …000000000101000000010 |
3 | 11202010121021222212122022 |
4 | 103200101120000220002 |
5 | 133424434223144132 |
6 | 2503422441041442 |
7 | 165556261045631 |
oct | 23402130005002 |
9 | 4663537885568 |
10 | 1340321303042 |
11 | 477477484a37 |
12 | 19791aa86282 |
13 | 995128c6037 |
14 | 48c2c6b3518 |
15 | 24ce8c27e12 |
hex | 13811600a02 |
1340321303042 has 4 divisors (see below), whose sum is σ = 2010481954566. Its totient is φ = 670160651520.
The previous prime is 1340321302993. The next prime is 1340321303093. The reversal of 1340321303042 is 2403031230431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1138764302641 + 201557000401 = 1067129^2 + 448951^2 .
It is a super-2 number, since 2×13403213030422 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335080325759 + ... + 335080325762.
Almost surely, 21340321303042 is an apocalyptic number.
1340321303042 is a deficient number, since it is larger than the sum of its proper divisors (670160651524).
1340321303042 is an equidigital number, since it uses as much as digits as its factorization.
1340321303042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670160651523.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1340321303042 its reverse (2403031230431), we get a palindrome (3743352533473).
The spelling of 1340321303042 in words is "one trillion, three hundred forty billion, three hundred twenty-one million, three hundred three thousand, forty-two".
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