13403235938 has 4 divisors (see below), whose sum is σ = 20104853910. Its totient is φ = 6701617968.

The previous prime is 13403235893. The next prime is 13403235983. The reversal of 13403235938 is 83953230431.

13403235938 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13403235893) and next prime (13403235983).

It can be written as a sum of positive squares in only one way, i.e., 12384796369 + 1018439569 = 111287^2 + 31913^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13403235895 and 13403235904.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350808983 + ... + 3350808986.

Almost surely, 2^13403235938 is an apocalyptic number.

13403235938 is a deficient number, since it is larger than the sum of its proper divisors (6701617972).

13403235938 is an equidigital number, since it uses as much as digits as its factorization.

13403235938 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6701617971.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 13403235938 in words is "thirteen billion, four hundred three million, two hundred thirty-five thousand, nine hundred thirty-eight".