13403243412401 has 4 divisors (see below), whose sum is σ = 13592021488704. Its totient is φ = 13214465336100.

The previous prime is 13403243412347. The next prime is 13403243412443. The reversal of 13403243412401 is 10421434230431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13403243412401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13403243412451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94389038045 + ... + 94389038186.

It is an arithmetic number, because the mean of its divisors is an integer number (3398005372176).

Almost surely, 2^{13403243412401} is an apocalyptic number.

It is an amenable number.

13403243412401 is a deficient number, since it is larger than the sum of its proper divisors (188778076303).

13403243412401 is an equidigital number, since it uses as much as digits as its factorization.

13403243412401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188778076302.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13403243412401 its reverse (10421434230431), we get a palindrome (23824677642832).

The spelling of 13403243412401 in words is "thirteen trillion, four hundred three billion, two hundred forty-three million, four hundred twelve thousand, four hundred one".