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134033230213444 = 2233508307553361
BaseRepresentation
bin11110011110011100001011…
…000100110011000101000100
3122120120110012021012201220001
4132132130023010303011010
5120032000023413312234
61153022003234451044
740142403251651422
oct3636341304630504
9576513167181801
10134033230213444
11397861a0242011
1213048655733a84
1359a3382a326c3
142515358958112
1510767a2a47d14
hex79e70b133144

134033230213444 has 6 divisors (see below), whose sum is σ = 234558152873534. Its totient is φ = 67016615106720.

The previous prime is 134033230213409. The next prime is 134033230213483. The reversal of 134033230213444 is 444312032330431.

134033230213444 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 125874711972100 + 8158518241344 = 11219390^2 + 2856312^2 .

It is a super-2 number, since 2×1340332302134442 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16754153776677 + ... + 16754153776684.

Almost surely, 2134033230213444 is an apocalyptic number.

It is an amenable number.

134033230213444 is a deficient number, since it is larger than the sum of its proper divisors (100524922660090).

134033230213444 is a wasteful number, since it uses less digits than its factorization.

134033230213444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33508307553365 (or 33508307553363 counting only the distinct ones).

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 134033230213444 its reverse (444312032330431), we get a palindrome (578345262543875).

The spelling of 134033230213444 in words is "one hundred thirty-four trillion, thirty-three billion, two hundred thirty million, two hundred thirteen thousand, four hundred forty-four".

Divisors: 1 2 4 33508307553361 67016615106722 134033230213444