Base | Representation |
---|---|
bin | 10011100000010010000… |
… | …110001001111111101001 |
3 | 11202010122010202110121022 |
4 | 103200102012021333221 |
5 | 133430000322300131 |
6 | 2503423552222225 |
7 | 165556465631066 |
oct | 23402206117751 |
9 | 4663563673538 |
10 | 1340333400041 |
11 | 477483297659 |
12 | 197922b3a975 |
13 | 9951527021c |
14 | 48c30141c6d |
15 | 24ce9d1737b |
hex | 13812189fe9 |
1340333400041 has 8 divisors (see below), whose sum is σ = 1371529199040. Its totient is φ = 1309138749072.
The previous prime is 1340333400019. The next prime is 1340333400089. The reversal of 1340333400041 is 1400043330431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1340333400041 - 210 = 1340333399017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1340333300041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2354900 + ... + 2868138.
It is an arithmetic number, because the mean of its divisors is an integer number (171441149880).
Almost surely, 21340333400041 is an apocalyptic number.
It is an amenable number.
1340333400041 is a deficient number, since it is larger than the sum of its proper divisors (31195798999).
1340333400041 is an equidigital number, since it uses as much as digits as its factorization.
1340333400041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 574015.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1340333400041 its reverse (1400043330431), we get a palindrome (2740376730472).
The spelling of 1340333400041 in words is "one trillion, three hundred forty billion, three hundred thirty-three million, four hundred thousand, forty-one".
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