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1340333400041 = 4360733513239
BaseRepresentation
bin10011100000010010000…
…110001001111111101001
311202010122010202110121022
4103200102012021333221
5133430000322300131
62503423552222225
7165556465631066
oct23402206117751
94663563673538
101340333400041
11477483297659
12197922b3a975
139951527021c
1448c30141c6d
1524ce9d1737b
hex13812189fe9

1340333400041 has 8 divisors (see below), whose sum is σ = 1371529199040. Its totient is φ = 1309138749072.

The previous prime is 1340333400019. The next prime is 1340333400089. The reversal of 1340333400041 is 1400043330431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340333400041 - 210 = 1340333399017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340333300041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2354900 + ... + 2868138.

It is an arithmetic number, because the mean of its divisors is an integer number (171441149880).

Almost surely, 21340333400041 is an apocalyptic number.

It is an amenable number.

1340333400041 is a deficient number, since it is larger than the sum of its proper divisors (31195798999).

1340333400041 is an equidigital number, since it uses as much as digits as its factorization.

1340333400041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 574015.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 1340333400041 its reverse (1400043330431), we get a palindrome (2740376730472).

The spelling of 1340333400041 in words is "one trillion, three hundred forty billion, three hundred thirty-three million, four hundred thousand, forty-one".

Divisors: 1 43 60733 513239 2611519 22069277 31170544187 1340333400041