1340334333 has 12 divisors (see below), whose sum is σ = 2084964700. Its totient is φ = 824821056.

The previous prime is 1340334319. The next prime is 1340334343. The reversal of 1340334333 is 3334330431.

It can be written as a sum of positive squares in 2 ways, for example, as 531671364 + 808662969 = 23058^2 + 28437^2 .

It is not a de Polignac number, because 1340334333 - 2¹² = 1340330237 is a prime.

It is a super-2 number, since 2×1340334333² = 3592992248437109778, which contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1340334297 and 1340334306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340334343) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5727808 + ... + 5728041.

Almost surely, 2^1340334333 is an apocalyptic number.

1340334333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1340334333 is a deficient number, since it is larger than the sum of its proper divisors (744630367).

1340334333 is a wasteful number, since it uses less digits than its factorization.

1340334333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11455868 (or 11455865 counting only the distinct ones).

The product of its (nonzero) digits is 11664, while the sum is 27.

The square root of 1340334333 is about 36610.5767914137. The cubic root of 1340334333 is about 1102.5654537166.

Adding to 1340334333 its reverse (3334330431), we get a palindrome (4674664764).

The spelling of 1340334333 in words is "one billion, three hundred forty million, three hundred thirty-four thousand, three hundred thirty-three".