13403402303 has 4 divisors (see below), whose sum is σ = 13417264080. Its totient is φ = 13389540528.

The previous prime is 13403402297. The next prime is 13403402317. The reversal of 13403402303 is 30320430431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30320430431 = 31 ⋅978078401.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13403402303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403402003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6929438 + ... + 6931371.

It is an arithmetic number, because the mean of its divisors is an integer number (3354316020).

Almost surely, 2^13403402303 is an apocalyptic number.

13403402303 is a deficient number, since it is larger than the sum of its proper divisors (13861777).

13403402303 is an equidigital number, since it uses as much as digits as its factorization.

13403402303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13861776.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 13403402303 its reverse (30320430431), we get a palindrome (43723832734).

The spelling of 13403402303 in words is "thirteen billion, four hundred three million, four hundred two thousand, three hundred three".