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1340340535 = 5268068107
BaseRepresentation
bin100111111100011…
…1111100100110111
310110102002100120001
41033320333210313
510221111344120
6341000052131
745133464232
oct11770774467
93412070501
101340340535
11628650756
12314a64047
131848c0811
14ca022419
157ca0ce0a
hex4fe3f937

1340340535 has 4 divisors (see below), whose sum is σ = 1608408648. Its totient is φ = 1072272424.

The previous prime is 1340340499. The next prime is 1340340559. The reversal of 1340340535 is 5350430431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5350430431 = 17377307903.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340340535 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134034049 + ... + 134034058.

It is an arithmetic number, because the mean of its divisors is an integer number (402102162).

Almost surely, 21340340535 is an apocalyptic number.

1340340535 is a deficient number, since it is larger than the sum of its proper divisors (268068113).

1340340535 is an equidigital number, since it uses as much as digits as its factorization.

1340340535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 268068112.

The product of its (nonzero) digits is 10800, while the sum is 28.

The square root of 1340340535 is about 36610.6614936141. The cubic root of 1340340535 is about 1102.5671543123.

Adding to 1340340535 its reverse (5350430431), we get a palindrome (6690770966).

The spelling of 1340340535 in words is "one billion, three hundred forty million, three hundred forty thousand, five hundred thirty-five".

Divisors: 1 5 268068107 1340340535